All these questions you keep asking are found either on wikipedia or in any textbook on the subject.
Also, its sort of pointless to explain what nonabelian anomalies are if you don't know what diagonalization means and is used for. There's a separation of about 4 years worth of undergrad material before the latter makes sense.
So if you truly are interested in all this physics material, I highly recommend starting from the beginning and working your way through step by step. Otherwise its all going to be hopelessly opaque and serves no purpose other than to clutter the board up.
#3
meopemuk
1,768
69
captain said:
how exactly does it work and how is it useful in qm?
The stationary Schroedinger equation
H | \Psi_n \rangle = E_n|\Psi_n \rangle...(1)
is used to find eigenvectors | \Psi_n \rangle and eigenvalues E_n (allowed energy spectrum) of the Hamiltonian H. Since Hamiltonian H is a linear operator, it can be represented by a matrix in an appropriate basis. Then eq. (1) becomes the traditional matrix diagonalization problem.
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated...
Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/
by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
I don't know why the electrons in atoms are considered in the orbitals while they could be in sates which are superpositions of these orbitals? If electrons are in the superposition of these orbitals their energy expectation value is also constant, and the atom seems to be stable!