How Far and Fast Does Tina Drive to Pass David?

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To determine how far Tina drives before passing David, the equations of motion are applied, considering David's constant speed and Tina's steady acceleration. Tina accelerates from rest at 2.20 m/s², while David maintains a speed of 26.0 m/s. By calculating the time it takes for Tina to catch up with David, the distance she travels can be found using the formula for distance under constant acceleration. Additionally, her speed at the moment she passes David can be calculated using her acceleration. The problem involves understanding relative motion and applying kinematic equations effectively.
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Homework Statement




David is driving at a steady 26.0m/s when he passes Tina who is sitting in her car at rest. Tina begins to accelerate at a stead 2.20 m/s2 at the instant when david passes.

Questions to answer:
1) How far does Tina drive before passing David?

2)What is her speed as she passes him?
 
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