How Far Does the Block Slide Before Coming to Rest?

  • Thread starter Thread starter renaldocoetz
  • Start date Start date
  • Tags Tags
    Block Bullet Wood
AI Thread Summary
The discussion focuses on a physics problem involving a bullet embedding into a block and sliding on a surface with kinetic friction. The key point is to use conservation of momentum to determine the initial velocity of the block and bullet system after the collision, as the bullet comes to rest instantly within the block. The work-energy theorem is then applied to relate the work done by friction to the change in kinetic energy. Participants clarify that the coefficient mentioned should be kinetic friction, not kinetic energy. The correct approach involves calculating initial kinetic energy using momentum conservation and then applying the work-energy principle to find the distance the block slides before coming to rest.
renaldocoetz
Messages
33
Reaction score
0

Homework Statement



Consider a bullet of mass m fired at a speed of V0 into a wooden block of mass M. The bullet instantaneously comes to rest in the block. The block with the embedded bullet slides along a horizontal surface with a coefficient of kinetic energy \mu.
How far does the block slide before it comes to rest? Express your answer in terms of m, M, \mu and g.

Homework Equations



W = Fs

W = KEf - KE0

where s = displacement

The Attempt at a Solution



I started by saying W = Fs and thought the only net force working here is kinetic friction.
so W = FN \mu s and since FN = mg i said...
W = (m +M)g \mus

then i said since W = KEf - KE0 ...
(m + M)g\mus = KEf - KE0

is this the right appoach?

I can't use conservation of momentum since the sum of external forces arent 0, I am assuming since they give the coefficient of kinetic friction.
 
Physics news on Phys.org
Yes, you can use conservation of momentum. The problem says that the bullet stops instantly. This means that the collision is completed before the block starts moving, i.e. before the external force of friction with the table starts acting on the block. You need to conserve momentum to find the initial velocity of the block+bullet system.
 
OK it seems i missread. It says "coefficient of kinetic energy", not "coefficient of kinetic friction".

Either way I am really clueless as to how to proceed :( Especially how to eventually get to distance. How do i know when to use conservation of momentum and when to use conserv of Kinetical Energy?
 
It should be coefficient of kinetic friction. It is safe to say that you conserve momentum when you have a collision, when two objects come together or push each other apart. As far as energy conservation is concerned, one usually talks about conservation of mechanical energy, which the sum of kinetic and potential energy. You conserve that when there are no dissipative forces such as friction or air resistance. If there are such things present (there is usually wording in the problem to indicate one way or the other), you have to use the work-energy theorem that says that the change in kinetic energy is equal to the net work (work done by the net force).

In answer to your question, yes your approach is correct. All you need to do is find KE0. You do that by conserving momentum for the part of the motion where the bullet embeds itself in the block.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top