How far does the particle travel?

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AI Thread Summary
A particle with a charge of -1.7 µC and mass 2.25 x 10^-3 kg is fired towards a fixed charge of -1.8 µC from a distance of 0.0450 m with an initial speed of 65.0 m/s. The key to solving the problem lies in applying the principle of conservation of energy, specifically using the equation KE + PE = constant. Users express confusion over how to incorporate potential energy (PE) into their calculations. The discussion emphasizes the need for clarity on the relationship between kinetic energy (KE) and potential energy (PE) in this context. Understanding these concepts is crucial for determining how far the particle travels before coming to a stop.
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Homework Statement



A charge of -1.8 µC is fixed in place. From a horizontal distance of 0.0450 m, a particle of mass 2.25 10-3 kg and charge -1.7 µC is fired with an initial speed of 65.0 m/s directly toward the fixed charge. How far does the particle travel before its speed is zero?

Homework Equations



q(V) = 1/2mv^2 (??)

The Attempt at a Solution



I'm afraid I'm very lost on this one. I messed around with the equation for collisions a bit but I can't seem to get in the right direction much less get the answer.

I would be grateful if you guys could provide me with some hints to get started >.<
thanks!
 
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hichangkyu said:
A charge of -1.8 µC is fixed in place. From a horizontal distance of 0.0450 m, a particle of mass 2.25 10-3 kg and charge -1.7 µC is fired with an initial speed of 65.0 m/s directly toward the fixed charge. How far does the particle travel before its speed is zero?

Hi hichangkyu! Welcome to PF! :smile:

Hint: just use KE + PE = constant. :smile:
 
I am having the same problem. I do not get KE + PE = constant?!
 
nckaytee said:
I am having the same problem. I do not get KE + PE = constant?!

Hi nckaytee! :smile:

KE = 1/2 mv2, and PE = … ? :smile:
 

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