How Far Is the Farther Slit from the Nearer Slit in a Double Slit Experiment?

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SUMMARY

The discussion centers on calculating the distance difference between the two slits in a double slit experiment, specifically for the m = 2 bright fringe with a light wavelength of 500 nm. The relevant equations include δ = r₂ - r₁ = d sin(θ) and d sin(θ_bright) = mλ. The conclusion is that without specific values for the slit separation (d) or the angle (θ), a precise numerical solution cannot be determined, and the distance difference is generally expressed as two wavelengths (2λ).

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  • Understanding of wave interference principles
  • Familiarity with the double slit experiment
  • Knowledge of the equations governing wave optics
  • Basic trigonometry for angle calculations
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  • Learn about the impact of slit separation on interference patterns
  • Explore the concept of fringe spacing in wave optics
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Homework Statement



Light of wavelength 500 nm illuminates a double slit, and the interference pattern is observed on the screen. At the position of the m = 2 bright fringe, how much farther is it to the farther slit than to the nearer slit?


Homework Equations



[tex]\delta= r_{2}-r_{1}=dsin(\theta)[/tex]
[tex]dsin(\theta_{bright})=m\lambda[/tex]


The Attempt at a Solution



Am I wrong in thinking that it is impossible to get a specific solution to this problem? Without being given the distance the slits are apart, d, or the theta angle the problem can only be solved generally, correct?
 
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Wouldn't it just be two wavelengths?
 

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