How far the aircraft slides before it comes to rest ?

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An aircraft making an emergency landing without landing gear at a speed of 40 m/s and a friction coefficient (μ) of 0.5 will slide a significant distance before coming to rest. The equation used to calculate the stopping distance is X = 2μg/v². The initial calculation resulted in 2 meters, but a more accurate calculation suggests the distance is approximately 1600 meters. The discussion also raises a comparison to car stopping distances, questioning whether they would stop in the same distance under similar conditions. Understanding the physics behind sliding friction is crucial for accurate predictions in emergency landing scenarios.
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Homework Statement


An aircraft has to make an emergancey landing on a runway
without landing gear , if the aircraft lands at 40 m\s-1
and μ is 0.5 ,
How far the aircraft slides before it comes to rest ?



Homework Equations


X=2 μ g \ v2


The Attempt at a Solution


2 x 0.5 \ 20 = 2 m ?
Using some website calculater result was : 1600 m
I'm terribly lost
 
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Any help please
 
Then compare with a car, do you think they equally stop at same distance.?
 
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