How Fast Can a Car Travel on a 22° Icy Banked Curve with a 170m Radius?

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The discussion centers on calculating the maximum speed a car can travel on a 22° banked curve with a radius of 170 m under icy conditions, where friction is negligible. Participants emphasize the importance of understanding centripetal acceleration and the forces acting on the car, including gravitational force and normal force. A free body diagram (FBD) is mentioned as a crucial tool for visualizing these forces and applying Newton's second law. The conversation highlights the need to identify which forces contribute to centripetal acceleration and how mass factors into the calculations. Overall, the thread seeks clarity on the relationship between forces and motion in this specific scenario.
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A curve of radius 170 m is banked at an angle of 22°. At what speed can it be negotiated under icy conditions where friction is negligible?

Can someone explain how to get the answer for this question? Thanks
 
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it concerns centripetal acceleration. did you try it at all? you need to at least show some of your work or thought processes.
 
Ok
I drew out the FBD

Fg going down
Fny going up
Fnx going to the right
Fn going at a 68 degree angle to the horizontal

Using the trig functions, I got: (not to significant figures)
Fg = 9.8 [N]
Fn = 9.8 [N]
Fnx = 3.96 [N]
Fn = 10.57 [N]

Ac = (Vc^2)/(r)
Fc = MAc = (MVc^2)/(r)
 
this is for your "1 kg" car, right?

which of these Forces is center-pointing?
 
Fnx is center pointing

The mass is not given
Apparently the masses should cancel out with teh formulas but I don't really know which ones to choose
 
What does Fc mean? That is to say, in your last equation, what is the meaning of Fc by itself, making no reference to the rest of the equalities on that line?

Hint: how does Fc relate to your FBD?
 
robphy said:
What does Fc mean? That is to say, in your last equation, what is the meaning of Fc by itself, making no reference to the rest of the equalities on that line?

Hint: how does Fc relate to your FBD?

Its going towards the center
 
Why does one draw a FBD in the first place?
How does it help you correctly apply Newton-II? In fact, what is the precise statement of Newton-II?
 
robphy said:
Why does one draw a FBD in the first place?
How does it help you correctly apply Newton-II? In fact, what is the precise statement of Newton-II?

Netforce(X/Y) = MA
 
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