How Fast Does a Ball Move When Pushed by Compressed Air?

AI Thread Summary
The discussion focuses on calculating the final velocity of a 1.72 kg ball propelled by compressed air in a 1.50 m tube, with an upward force of 28.7 N. Participants clarify that the downward force acting on the ball is its weight, calculated as mass times gravity, rather than friction, which is not mentioned in the problem. The correct approach involves using Newton's second law to find acceleration and then applying the kinematic equation to determine the final velocity just before the ball exits the tube. It is confirmed that the initial velocity can be assumed to be zero for this calculation. The conversation emphasizes understanding the forces at play and the proper application of physics equations to solve the problem.
brunettegurl
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final velocity of a ball pushed by compressed air..pls. help!

Homework Statement


Compressed air is used to fire a 1.72 kg ball vertically upward from a 1.50 m long
tube. The air exerts a upward force of 28.7 N on the ball as long as it is in the tube.
With what velocity does the ball leave the top of the tube?


Homework Equations


F=ma
V12 = v02+2ad


The Attempt at a Solution


so i used the given mass and force to get an acceleration. then using the acceleration i plugged it into the second equation assuming vinitial to be zero and my asnwer is coming out wrong can someone point me in the right direction thanks :))
 
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Resultant force= Upward force-downward force

what's the downward force in this case?
 


wld the downward force be the friction..but there is no mention of any friction in the question
 


brunettegurl said:
wld the downward force be the friction..but there is no mention of any friction in the question

if you throw a ball upwards, it does not continue to go upwards, what makes it fall back to earth? (it has a mass m and is under the influence of gravity g)
 


ok but that tells us what happens after it is released they're asking for velocity just before it's released from the cannon/tube
 


brunettegurl said:
ok but that tells us what happens after it is released they're asking for velocity just before it's released from the cannon/tube

When you find the resultant force, you can get the resultant acceleration...:wink:

and in the formula v_1^2=v_0^2+2ad

what do you need to find to get the value for v1?
 


we have the distance(1.50) and we now have an acceleration but would vinitial still be equal to zero??
 


brunettegurl said:
we have the distance(1.50) and we now have an acceleration but would vinitial still be equal to zero??

Yes it would be safe to assume the initial velocity as zero.
 


thank you so much :))
 
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