How Fast Does a Rock Accelerate When Swung on a String?

  • Thread starter Thread starter tman
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
When a rock is swung in a circle at a constant speed of 25 ft/sec with a string length of 1.765 ft, its centripetal acceleration can be calculated using the formula a = v²/r. Substituting the values, acceleration equals (25 ft/sec)² divided by 1.765 ft. This results in an acceleration of approximately 354 ft/sec² when rounded to the nearest whole number. The discussion also suggests utilizing homework help forums for similar questions. Understanding centripetal acceleration is crucial for solving such physics problems effectively.
tman
Messages
15
Reaction score
0
A rock tied to a string is swung around in a circle at a constant speed of 25 ft/sec. The length of the string is 1.765 ft. Calculate the acceleration. (Round to nearest whole number.)

acceleration = ________ft/sec2
 
Physics news on Phys.org
You know, there is a homework help forum. You might post questions of that nature there.

That said, centripetal acceleration is equal to \frac{v^2}{r}.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top