How Fast Does Ozone Travel After Collision?

  • Thread starter Thread starter Voltrical
  • Start date Start date
  • Tags Tags
    Velocity
AI Thread Summary
The discussion focuses on a physics problem involving the collision of an oxygen molecule and an oxygen atom to form an ozone molecule. The initial velocities and masses are provided, and the conservation of momentum is applied to determine the resulting velocity of the ozone. The calculated velocity is 645 m/s in the x-direction. A participant questions whether the ozone molecule has a zero y-component of velocity, prompting a consideration of momentum conservation in both x and y directions. The importance of analyzing both components is emphasized for accuracy in the solution.
Voltrical
Messages
11
Reaction score
0

Homework Statement



A 32-u oxygen molecule (O2) moving in the +x-direction at 580 m/s collides with an oxygen atom (mass 16 u) moving at 870 m/s at 27° to the x-axis. The particles stick together to form an ozone molecule. Find the ozone’s velocity.


Homework Equations





The Attempt at a Solution



m1 = 32 u,
v1 = 580i m/s,
m2 = 16 u,

v2 =870(cos(27) i + sin(27) j) m/s

m1 v1 + m2 v2 =(m1 + m2)V

V = (m1 v1+ m2 v2)/(m1+ m2) = (645 i) m/s

Answer = 645 i m/s

Does that look right?
 
Physics news on Phys.org
Conservation of momentum must hold for all components. You calculated the x component of velocity of the ozone molecule. Do you think it has zero y component of velocity?

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top