How fast does the disk move when pulled by a string?

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A solid uniform disk of mass 21.0 kg and radius 85.0 cm is pulled by a constant force of 35.0 N on a frictionless surface. The initial calculations for the disk's linear speed and angular velocity were incorrect, prompting a request for help. The correct approach involves applying Newton's second law and understanding the relationship between linear and angular motion. After receiving guidance, the original poster successfully resolved the problem. The discussion emphasizes the importance of correctly applying physics principles to solve motion-related problems.
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1. A solid uniform disk of mass 21.0 kg and radius 85.0 cm is at rest flat on a frictionless surface. A string is wrapped around the rim of the disk and a constant force of 35.0 N is applied to the string. The string does not slip on the rim.
(A) When the disk has moved a distance of 3.2 m, determine how fast it is moving.
(B) How fast it is spinning (in radians per second).
(C) How much string has unwrapped from around the rim.

Homework Equations


τ=RF
τ=Iα
I=.5mR^{2}
a=Rα
v^{2}=v^{2}_{0}+2ax
v=Rω

The Attempt at a Solution


(A) τ=RF=(35)(.85)=29.75
I=(.5)(21)(.85)^{2}=7.58625
α=τ/I=29.75/7.58625=3.92
a=(.85)(3.92)=3.33
v=\sqrt{0+(2)(3.33)(3.2)}=4.6
This is how I did the problem but it is incorrect.

(B)v=Rω
I want to use this formula to find the angular velocity but my velocity is incorrect.

(C)I was thinking of using this formula: θ=(ω^{2}-ω^{2}_{0})/2α

Can somebody please help me?
 
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kritzy said:
A solid uniform disk of mass 21.0 kg and radius 85.0 cm is at rest flat on a frictionless surface. A string is wrapped around the rim of the disk and a constant force of 35.0 N is applied to the string. The string does not slip on the rim.
(A) When the disk has moved a distance of 3.2 m, determine how fast it is moving.

τ=RF
τ=Iα

Hi kritzy! :smile:

For (A), use the ordinary (linear) version of Newton's second law :wink:
 
tiny-tim said:
Hi kritzy! :smile:

For (A), use the ordinary (linear) version of Newton's second law :wink:

I figured it out. Thank you for the hint.:smile:
 
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