How Fast is the Ball After a Perfectly Elastic Collision?

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In a perfectly elastic collision, both momentum and kinetic energy are conserved. For the given scenario, the initial momentum of the system can be calculated using the mass and velocity of the ball. The final velocities of both the ball and the block can be determined by applying the conservation of momentum and kinetic energy equations. The answer provided in the book indicates that the ball's speed after the collision is 3.3 m/s, which can be confirmed through the calculations involving these principles. Understanding and applying these conservation laws is essential for solving the problem accurately.
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A 100gram block is attached to the end of a spring on a frictionless table that has a spring constant of 20N/m. The other end of the spring is attached to the wall. A 20g ball is thrown at the block with a velocity of 5.0m/s.

If the collision is perfectly elastic, what is the ball's speed immediately after the collision.

I am unsure about how to solve this, I know that an elastic collision is one in which energy is conserved so the initial Kinetic energy of the ball is the systems total energy after collision. But what to do from there?



PS: answer in book says 3.3m/s
 
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But what to do from there?
Add momentum conservation, write down formulas and solve.
 

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