How fast is the car moving when

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The discussion revolves around calculating the speed of a car when a pebble dislodges from its tire tread due to acceleration. The net torque exerted on the pebble is calculated as 1.368 N-m, while the moment of inertia is determined to be 8.664 x 10^-5 kg-m^2. This results in an angular acceleration of 15789 rad/s^2. The challenge lies in finding the angle theta, as the distance traveled around the tire's circumference is unknown, complicating the calculation of when the centripetal force exceeds the static friction. Understanding the relationship between frictional and centripetal forces is crucial for determining when the pebble will fly out.
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A 1.2 g pebble is stuck in a tread of a .76 -m-diameter automobile tire, held in place by static friction that can be at most 3.6 N. The car starts from rest and gradually accelerates on a straight rode . How fast is the car moving when the pebble flies out of the tire tread?

Alpha= net Torque/moment of Inertia

So net torque is 3.6 * .38= 1.368 N-m. Moment of inertia is .5mr^2 so that's .5 * .0012 * .38 ^2= 8.664 * 10^-5. so 1.368 N-m/ (8.664 kg-m^2)= 15789 rad/s^2. Now I need to find Theta and then use wf^2= wi^2 + 2alpha * theta. Then use v=wr. But how do I find theta when I don't know the distance is has traveled around the circle. Is it 2pi*r? I am having trouble because how do I know how Many times this pebble went around the circle? I can't find theta if I don't know the full distance is traveled around the circle since theta= s/r where s is the distance the particle goes on it's circular path. How do I find theta?
 
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As long as the frictional force is greater than the centripetal force on the pebble, the pebble will stay in the tire thread. When the centripetal force is greater than the frictional force, the pebble will fly off.
 
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