How Fast Is the Shadow's Height Changing as the Dog Approaches the Wall?

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Homework Help Overview

The problem involves a spotlight casting a shadow of a dog onto a wall, with specific measurements provided. The context is related rates in calculus, focusing on how the height of the shadow changes as the dog approaches the wall.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the Pythagorean theorem and similar triangles to the problem. There is confusion regarding the correct approach to relate the dog's movement to the height of the shadow. Some participants suggest drawing a diagram to clarify relationships.

Discussion Status

The discussion is ongoing, with participants exploring different mathematical concepts and questioning the original poster's approach. Some guidance has been offered regarding the use of similar triangles instead of the Pythagorean theorem, indicating a productive direction.

Contextual Notes

There is a mention of the dog's height and the distance to the wall, but specific assumptions or constraints regarding the setup of the problem are not fully detailed. The original poster's terminology and equations are also under scrutiny.

venger
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Homework Statement


A spotlight on the ground shines on a wall 14m away. If a dog, 0.5m tall, runs from the spotlight towars the building at a speed of 1 m/s, how fast is the height of the animal's shadow on the building decreasing when the dog is 5 meters from the building?

Wrt = with respect to

Homework Equations


Pythagoreon theorem, implicit differentiation, you name it.


The Attempt at a Solution



Knowing that Dc/dt is canine wrt time is 1 m/s and i am trying to find dh/dt 'h' for height wrt time

and I am stuck...
.
..
...
14^2 + wall^2 = Hyp^2
 
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This is called a "related rates" problem, not "implicit differentiation."

dc/dt? if you're using the pythagorean theorem, that implies (at least to me) that the dog is running on the hypotenuse??

At a glance, I'm having a tough time getting the pythagorean theorem to really work for me on this problem. Have you thought about the angle made by the flashlight between the ground and the beam to the top of the dog? Or, have you thought about similar triangles?
 
You should have put "similar triangles", not "Pythagorean theorem", in "Relevant Equations". Can you draw a picture and see why?
 
Here i go furthering my development in related rates
let l be length of shadow and let x be ground covered with light
2/L = X/12
24=LX
L=24X^-1
dL/dt(1)=-24X^-2
dL/dt=-24(12-8)^-2
dL/dt=9/32
 

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