How Fast Must Wind Blow to Lift an Aluminum Sheet?

AI Thread Summary
To determine the minimum wind velocity required to lift a sheet of aluminum, one must calculate the weight per area of the sheet using its density and thickness. This weight per area corresponds to the pressure difference needed to create lift. By applying Bernoulli's equation, the velocity of the air above the sheet can be calculated, assuming still air below. The discussion emphasizes the importance of understanding pressure gradients similar to those experienced by an airplane wing. A clear understanding of these principles is essential for solving the problem effectively.
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Homework Statement



A sheet of aluminum of thickness .01 m lies in a parking lot. A wind blows over the top of the sheet. What is the minimum velocity that will cause the sheet to begin to rise: Assume the density of air is 1.18 kg/m^3 and aluminum is 2700 kg/m^3.

Homework Equations



Bernoulli's Equation:

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or

Archimedes Principal:

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Density = M/Vol

The Attempt at a Solution



I really have no idea where to start. Since the density of AL is different than that of the fluid, I would assume it to be a buoyant force. However, air is a strange fluid to work with, and I can't figure out the volume displaced.

I just need a hint on where to begin... maybe some links to other reading. All help would be vastly appreciated.

Thanks! Sean
 
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well its much like the lift on a wing where the difference in velocities leads to a pressure gradient across the sheet.
 
First figure out the weight per area of the aluminum sheet in N/m^2, based the numbers given. That weight per area is then the difference in pressure needed to lift the plate. Assume the air below the plate is still, and figure out how fast the air on top of it needs to be to create the pressure difference.
 
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