How Fast Was the Bullet After Passing Through the Ballistic Pendulum?

AI Thread Summary
The discussion focuses on calculating the velocity of a bullet after it passes through a ballistic pendulum block. A 9.05-g bullet traveling at 331.0 m/s strikes a 0.705-kg block and exits after rising 19.47 cm. The problem emphasizes using conservation of energy and momentum principles to find the bullet's final velocity. The initial kinetic energy of the bullet and the potential energy of the block are considered, leading to the need for a formula to relate these energies. The conversation highlights the challenge of applying these concepts correctly to solve the problem.
shigami117
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1. A 9.05- g bullet from a 9-mm pistol has a velocity of 331.0 m/s. It strikes the 0.705- kg block of a ballistic pendulum and passes completely through the block. If the block rises through a distance h = 19.47 cm, what was the velocity of the bullet as it emerged from the block? i know that this is supposed to be done using conservation of energy and momentum. but i can't get it
 
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It's still a conservation of energy.

Initial kinetic energy of bullet + initial potential energy of block (which is zero) -> final ke of bullet + final potential energy of block.
 
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