How force works on two strings connected by a mass

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SUMMARY

The discussion centers on the mechanics of two strings connected by a mass and the effects of pulling one string (A) on the other (B). When string A is pulled slowly, the tension in string B exceeds that in string A, causing string B to reach its breaking point first due to the additional weight (mg) acting on it. Conversely, if string A is pulled suddenly, the acceleration (a) increases significantly, resulting in greater tension in string A compared to string B, which allows string A to tear while string B remains intact. This phenomenon is explained using Newton's second law, where the net force equation illustrates the relationship between the forces acting on the strings and the mass.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic knowledge of tension in strings
  • Familiarity with concepts of force and acceleration
  • Knowledge of mass and gravitational force (mg)
NEXT STEPS
  • Study the applications of Newton's second law in different physical scenarios
  • Explore the concept of tension in multiple string systems
  • Investigate the effects of acceleration on force distribution in connected objects
  • Learn about material properties and breaking points of different strings
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Physics students, engineers, and anyone interested in mechanics and the behavior of forces in connected systems.

Ezio3.1415
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So if I slowly pull the A string first B string will tear apart... Cause the A string will expand and it will pull the mass and B string... So B string will reach its breaking weight before A... Cause B has an additional weight mg working on it..

But if I suddenly pull the A string,it will tear apart but the B string will remain intact... I am trying to understand why this happens... I mean what is the exact mechanism here?
 

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Applying Newton's second law to the block we have

Fnet = ma
FA - FB + mg = ma
FA - FB = m(a-g).

If you pull it slowly, acceleration a is negligible and we get

FA - FB = -mg < 0
FA < FB

FB is larger.

But if you pull very fast than a is very large and we get

FA - FB = m(a-g) >0

FA > FB

FA is larger.
 
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Thank you... :)
 

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