How High Does a Rocket Rise After Fuel Depletion?

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The discussion revolves around a physics homework problem involving a rocket's ascent and fuel depletion. The rocket accelerates at +30.0 m/s² for 5 seconds, reaching a height of 150 meters before running out of fuel. Participants emphasize the need to break down the problem into parts and apply relevant equations to find the maximum height after fuel depletion. Additionally, there are side discussions about other physics problems, highlighting the importance of showing work and understanding concepts rather than seeking direct answers. The thread underscores the collaborative nature of learning physics through problem-solving and discussion.
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Homework Statement


A rocket moves upward, starting from rest with an acceleration of +30.0 m/s2 for 5.00 s. It runs out of fuel at the end of this 5.00 s and continues to move upward for a while. How high does it rise above its original starting point?


Homework Equations



Hmm this is one of my homework questions i have like 5 more of these problems, can someone help solve this one showing a step by step.

The Attempt at a Solution


What i did was multiplied 30 x 5 to so 150m I don't understand what formula i should use to calculate the part 2 of this problem
 
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maaz224 said:

Homework Statement


A rocket moves upward, starting from rest with an acceleration of +30.0 m/s2 for 5.00 s. It runs out of fuel at the end of this 5.00 s and continues to move upward for a while. How high does it rise above its original starting point?


Homework Equations



Hmm this is one of my homework questions i have like 5 more of these problems, can someone help solve this one showing a step by step.

The Attempt at a Solution


What i did was multiplied 30 x 5 to so 150m I don't understand what formula i should use to calculate the part 2 of this problem

Welcome to the PF.

I've moved your question from the Advanced Physics forum to the Intro Physics forum. The Advanced Physics forum is for upper-division and graduate-level questions.

Also, per the PF rules (see the link at the top of the page), we don't do your schoolwork questions for you. We can provide hints, ask questions, check your work, etc., but you must do the bulk of the work.

So having said that, what can you do with each part of this problem? Break it down into the various parts (start, middle, end, etc.), and see what equations you can write for each part. Like, it has constant accelration for some amount of time at the start, so what can you say about it's speed and KE and PE at the point it runs out of fuel?
 
A tennis ball with a speed of 8.0 m/s is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 6.0 m/s. If the ball is in contact with the wall for 0.019 s, what is the average acceleration of the ball while it is in contact with the wall? Take the initial direction of motion to be the positive direction. (Indicate the direction of the acceleration by the sign of your answer.)

I actaully sovled the one above.. can someone help me with this one
 
Man... I am taking ap physics... LOL
 
maaz224 said:
A tennis ball with a speed of 8.0 m/s is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 6.0 m/s. If the ball is in contact with the wall for 0.019 s, what is the average acceleration of the ball while it is in contact with the wall? Take the initial direction of motion to be the positive direction. (Indicate the direction of the acceleration by the sign of your answer.)

I actaully sovled the one above.. can someone help me with this one

As I said already, you need to show some work. What is the definition of acceleration in terms of velocities and times?
 
Alright if its work you need... I am coming with it right now
 
8m/s would be its velocity, so accel equals Final v - iniital v /time = acceleration
 
Hmm but what i don't understand is... how will i be able to calculate final velocity iniital is 8 m/s
 
maaz224 said:
Hmm but what i don't understand is... how will i be able to calculate final velocity iniital is 8 m/s

The problem statement says that its velocity is 8m/s one way before hitting the wall, and 6m/s the other way after hitting the wall. What's the total delta-v?
 
  • #10
okay i understand thanks so the total v

-8+-6 SO -14 now we have the equation for accel which is a = total v/ Time so its -14/.019 so its 736.84 Nice
 
  • #11
A person takes a trip, driving with a constant speed of 94.5 km/h except for a 21.0 min rest stop. If the person's average speed is 65.6 km/h, how much time is spent on the trip and how far does the person travel?

LMAO i have no clue about this hw... ... what type of work am i suppose to show on this.. can someone give me a hint
 
  • #12
so far what i found was 65.6 = Distance (unknown) / x(time unknown) + 21 mins
 
  • #13
maaz224 said:
A person takes a trip, driving with a constant speed of 94.5 km/h except for a 21.0 min rest stop. If the person's average speed is 65.6 km/h, how much time is spent on the trip and how far does the person travel?

LMAO i have no clue about this hw... ... what type of work am i suppose to show on this.. can someone give me a hint

First of all, please start a new thread when you have a new question. It's too hard for folks trying to help if you append new questions on the end of an existing thread.

Second, the type of work you show is your try at figuring out the problem. Spoon feeding and hand holding you won't help you learn how to learn, and that's a big part of what we do at the PF.

So how should you approach a problem like this? Remember what I said a ways back in this thread about breaking a problem up into its parts. Break this up into parts, start labelling variables and things (like times t1, t2, etc.), and see how the whole thing looks to you.

Post your work and thoughts.
 
  • #14
maaz224 said:
so far what i found was 65.6 = Distance (unknown) / x(time unknown) + 21 mins

And he was going 94.5km/hr for the time x that you list... (maybe use t1 instead of x)
 
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