How High Does the Block Reach on a Moving Ramp?

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Homework Help Overview

The problem involves a block sliding up a moving ramp, where the block has an initial horizontal velocity and the ramp is inclined at an angle. The goal is to determine the highest point the block reaches before sliding back down, considering the absence of friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy and momentum, questioning how to apply these principles given the external forces involved. There is an exploration of impulse and its role in the problem, along with concerns about the net forces acting on the block and ramp system.

Discussion Status

Participants are actively engaging with the problem, raising questions about the definitions of impulse and net forces. Some have suggested focusing on conservation of energy while others are exploring the implications of momentum conservation in the absence of external horizontal forces. There is no explicit consensus yet, but multiple lines of reasoning are being explored.

Contextual Notes

There is a noted complexity due to the ramp's motion and the initial horizontal velocity of the block, which may affect the interpretation of forces and energy in the system. Participants are also considering the implications of the normal force and its components in the context of the problem.

datdo
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Difficult: Block sliding up moving ramp

Homework Statement



A block of mass m with initial velocity of v0 slides up up a ramp of angle [tex]\theta[/tex] and mass M that is not pinned to the ground. It doesn't reach the top before sliding back down. What is the highest point that the block reaches in terms on [tex]\theta[/tex], v0, and m. There is no friction between any surfaces.



Homework Equations



[tex]p = mv[/tex]
[tex]J=Ft[/tex]
[tex]E_i=E_f[/tex]

The Attempt at a Solution


[tex]E_i=E_f[/tex]
[tex].5mv_0^2=.5Mv_r^2+mgh[/tex]

[tex]p_i=p_f+J[/tex]
[tex]mv_0= Mv_r+Ft[/tex]<-at top height

[tex]F=mg+mgcos\theta[/tex]<-from standard block on ramp problems

Is this correct?
 

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Last edited:
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Welcome to PF.

What is I = Ft ? Impulse?

And what do you do with getting rid of F and t?

Maybe consider the conservation of energy as you were starting to do?

1/2mVo2 = (horizontal kinetic energy) + m*g*h

Focus on what the horizontal kinetic energy is at the top. And as well express h in terms of the distance up the ramp and θ.
 
I guess I should explain a bit:

First things I thought were energy is conserved but momentum is not due to a external net force but I can still work with momentum if I just figure out the impulse.

[tex]E_i = E_f[/tex]

[tex]p_i =p_f +J[/tex]

The problem I'm having is I don't know how to solve for time. Nor do I am I sure what the net force is. I know its due to gravity but I'm not sure how the weight and the normal force cancel.

Basically the question I'm really wondering is what is the impulse of this "collision"
 
datdo said:
I guess I should explain a bit:

First things I thought were energy is conserved but momentum is not due to a external net force but I can still work with momentum if I just figure out the impulse.

[tex]E_i = E_f[/tex]

[tex]p_i =p_f +J[/tex]

The problem I'm having is I don't know how to solve for time. Nor do I am I sure what the net force is. I know its due to gravity but I'm not sure how the weight and the normal force cancel.

Basically the question I'm really wondering is what is the impulse of this "collision"

Is there a drawing that shows the block initially traveling horizontally only? Or is the Vo initially directed up the incline?
 
v0 is completely horizontal
 
datdo said:
I guess I should explain a bit:

First things I thought were energy is conserved but momentum is not due to a external net force but I can still work with momentum if I just figure out the impulse.
There's no external horizontal force on the system, so momentum is conserved in that direction. Find the speed of system when the block reaches the highest point, then use LowlyPion's hint in post #2.
 
but the normal force due to the ramp has a horizontal component which is not canceled by any other force.

Also if there were no horizontal force the block would continue moving to the right. Newton's first law.

Also in response to LowlyPion:

Energy is a scalar so you can't take components of it.
 
Last edited:
datdo said:
but the normal force due to the ramp has a horizontal component which is not canceled by any other force.

Also if there were no horizontal force the block would continue moving to the right. Newton's first law.
Of course if you look at the block alone, then there's an unbalanced force on it. Instead of doing that, look at the block + ramp as a single system. There are no external horizontal forces on the system, thus the momentum of the system is conserved in that direction.
 

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