How High Will a Toboggan Go Up an Icy Hill?

[bertoline]

Homework Statement

At the base of a frictionless icy hill that rises at 29.0deg above the horizontal, a toboggan has a speed of 12.0 m/s toward the hill. How high vertically above the base will it go before stopping?

Homework Equations

Wtot=K2-K1
K=1/2mv^2
K2=1/2mv^2=K1+Wtot

The Attempt at a Solution

Vx=12cos(29) = 10.5 m/s
vf^2-vi^2=2as
0-(10.5)^2=2(-9.8)s
s= 5.625

 

[AFG34]

This is how i would do it:
1. draw an fbd of the toboggan
2. use f=ma to solve for a
3. solve for distance traveled on the hill
4. then you make a triangle, with the distance you found in 3) being the hypotenuse, solve for the vertical side, and that's how high it has travelled.