How High Will the Bullet-Carrying Cart Climb the Ramp?

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The discussion centers on a physics problem involving a bullet embedded in a cart that rolls up a ramp. A 15 g bullet traveling at 150 m/s strikes a low-friction cart weighing 0.5 kg, and the goal is to determine the maximum height the cart will reach on a 30-degree incline. The initial calculations yield a velocity of 4.37 m/s for the cart after the collision, which is adjusted for the ramp's angle to 5.04 m/s. The height is then calculated using energy conservation principles, leading to confusion about the correct approach. Ultimately, the key equations involve momentum conservation and gravitational potential energy to find the maximum height reached by the cart.
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Homework Statement



At a crime lab, they are experimenting measuring the speed of bullets. In it, a 15 g bullet is fired at 150 m/s into a wood block mounted on a low-friction cart (m=0.5kg). The bullet imbeds in the cart and the cart then rolls up a 30-degree ramp. Ignoring friction, predict the max height that the cart will rise to as it rolls up the lamp.

Homework Equations





The Attempt at a Solution



.015(150)+0=(.5+.015)vx

vx=4.37 ms

since it's a 30 degree angle.. the velocity of cart=4.37/cos(30)=5.04 m/s

x=(vf^2-vo^2)/2a
=(5.04^2-0)/2(9.8)
-1.2?

i don't know if this was correct.
 
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Why not just say mgh=.5m(vx)^2

h = sqrt(4.37^2/20)
 
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