(How) is a single photon polarized?

  • Thread starter Richard J
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In summary: In the quantum world, however, things are a bit more complicated.The wave function of a single photon is not a single vector, but rather a collection of quanta (photons).Each photon has a spin quantum number, which corresponds to a particular orientation of the quanta in the wavefunction.This spin quantum number is 1 for a single photon, and +/- 1 for two photons.In general, the two polarization vectors can be written as:\vec{p} = \vec{p}_1 + \vec{p}_2where \vec{p}_1 and \vec{p}_2 are the vectors in the direction of the spin quantum numbers of the two photons.However,
  • #1
Richard J
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What quantum mechanical property of the photon determines its polarization?
Can a single photon be unpolarized?
Can a single photon be linear polarized?
Can a single photon be circular polarized?
Can a single photon's polarization be changed?

Can classical and quantum mechanical polarization of an electromagnetic wave/photon coexist?


Richard
 
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  • #2
Photons are bosons and have spin [tex]\pm[/tex] 1, corresponding to two different circular polarization modes. One photon has one of these two, and other modes of polarization are achieved by superposition of more photons.
 
  • #3
Actually the spin quantum number of a photon is 1 and +/- 1 is the helicity (helicity quantum numbers).
 
  • #4
Does the spin quantum number or the helicity quantum number of the photon correspond to the classical concept of electromagnetic wave polarization?
 
  • #5
The Wikipedia article on Photon Polarization says that the spin corresponds to classical polarization.
 
  • #6
Ok let me just writ it out it's simplest this way
The free electromagnetic potential is given by:

[tex]
a^\mu (x) = (2\pi )^{ - 3/2} \int {\frac{{d^3 p}}
{{\sqrt {2p^0 } }}} \sum\limits_\sigma {\left[ {e^{ip \cdot x} e^\mu ({\mathbf{p}},\sigma )a({\mathbf{p}},\sigma ) + e^{ - p \cdot x} e^{\mu *} ({\mathbf{p}},\sigma )a^\dag ({\mathbf{p}},\sigma )} \right]}
[/tex]

Now, [tex]
e^\mu ({\mathbf{p}},\sigma )
[/tex] that represents the direction of the field is called a polarization vector.
[tex]
\sigma
[/tex] the helicity can be thought of as in which direction the polarization vector is rotating clockwise or counterclockwise.
 
  • #7
This very similar to the classical situation.

Classically for a single monochromatic plane wave, if you pick your coordinates properly, the wave can be written in the general form:

[tex]
{\mathbf{A}} = B\cos (kz - \omega t){\mathbf{x}} \pm C\sin (kz - \omega t){\mathbf{y}}
[/tex] where B and C are the polarizations of the wave, elliptical in general, and the [tex]
\pm[/tex] symbol represents the helicities which just determine the direction of rotation of the polarized wave.
 

1. What does it mean for a photon to be polarized?

Polarization refers to the orientation of the electric field of a photon. A polarized photon has its electric field oscillating in a specific direction, while an unpolarized photon has its electric field oscillating in all directions.

2. How is a photon's polarization determined?

A photon's polarization is determined by the direction of its electric field, which can be affected by the direction of the photon's travel or by passing through certain materials.

3. Can a single photon have multiple polarizations?

No, a single photon can only have one polarization at a time. However, the polarization of a photon can change when it interacts with matter or other photons.

4. How is a photon's polarization used in scientific research?

The polarization of a photon is used in various fields of research, including optics, quantum mechanics, and astronomy. It can provide valuable information about the properties of particles and the behavior of light.

5. Can a photon's polarization be manipulated?

Yes, a photon's polarization can be manipulated using polarizing filters, birefringent crystals, or other methods. This is important in technologies such as 3D glasses, LCD screens, and quantum computing.

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