How Is Air Pressure Calculated in a Crushed Can Experiment?

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The discussion focuses on calculating the total force exerted on a crushed can due to air pressure in a physics experiment. The can's dimensions are provided, and the method involves calculating the area of the can's sides and using the atmospheric pressure value of 101300 Pa. The area is determined to be approximately 0.2132 m², leading to a calculated force of about 21594.16 N when multiplied by the pressure. The calculations appear to be correct based on the provided methodology. This experiment effectively demonstrates the impact of air pressure on a sealed container.
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Homework Statement



A rectangular metal can with dimensions of 0.234 meters by 0.194 meters by 0.143 meters is used in a physics demonstration to show the force exerted by air pressure. A small quantity of water is poured into the can and brought to a boil. Then the can is capped and allowed to cool, which crushes the can. What is the total force exerted on the can by the air around it, assuming a perfect vacuum inside?

Homework Equations



1 atm = 101300 Pa

The Attempt at a Solution



so just find the area of each of the three sides and multiply by 2

so 2(.234*.194)+2(.194*.143)+2(.234*.143)
and so i got .2132 m^2

so then we know

101300 Pa = N/m^2

so 101300pa * .2132 m^2 = N

so N = 21594.16

am i right?
 
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