How Is Carbon Calculated in Cementite and What Is Its Role in Pearlite?

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Cementite, represented by the formula Fe3C, consists of three iron atoms and one carbon atom, making a total of four atoms. The atomic percentage of carbon in cementite is 25%, while the atomic percentage of iron is 75%. To calculate weight percentage, the contributions based on atomic weights yield approximately 6.67% carbon and 93.33% iron by weight. Cementite appears on the Fe-C phase diagram as a distinct phase, critical for the formation of pearlite, where it enhances hardness and strength. Understanding these calculations and properties is essential for analyzing the role of cementite in steel microstructures.
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Fe3C Cementite HELP PLEASE!

Hello... I was wondering if someone would be able to help with the follow question...

Cementite: consider cementite. Calculate the amount of carbon in Cementite (1) as atomic % (2) as weight % [atomic weights Fe 56, c 12]. Place cementite on the Fe-C phase diagram; explain the nature of its appearance on the diagram, and comment on the nature and properties of cementite. Cementite is a key part of pearlite- how does it contribute to the structure of pearlite?

I totally understand the question apart from the atomic % and the weight %, if someone could help i would be so grateful, thanks.
 
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The formula is Fe3C. That is three iron atoms per carbon. Express that ratio in terms of atoms Fe:total atoms in the formula to get Fe atomic %. Also find C:total atoms in the formula to get C atomic %. Convert that to weight to get Weight %.
 


chemisttree said:
The formula is Fe3C. That is three iron atoms per carbon. Express that ratio in terms of atoms Fe:total atoms in the formula to get Fe atomic %. Also find C:total atoms in the formula to get C atomic %. Convert that to weight to get Weight %.

could you give me a example as this really isn't my strong point, thanks
 


Fe3C contains ___ iron atoms, ___ carbon atoms, and ___ atoms in total.
Using those numbers, what percentage of the total atoms are carbon?
 
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