How Is Energy Transferred in a Refrigeration Compressor System?

Click For Summary
SUMMARY

The discussion focuses on the energy transfer in a refrigeration compressor system using Refrigerant 134a. The refrigerant enters the compressor as saturated vapor at 0.14 MPa and exits as superheated vapor at 0.8 MPa and 50 degrees Celsius, with a mass flow rate of 0.04 kg/s. Key calculations involve determining energy transfer rates by mass, emphasizing that mass is not needed for per unit mass energy calculations. The kinetic energy per unit mass is calculated using the formula V²/2, and thermodynamic properties are expressed on a per unit mass basis.

PREREQUISITES
  • Understanding of thermodynamic properties, specifically specific enthalpy and internal energy.
  • Knowledge of the continuity equation in fluid dynamics.
  • Familiarity with the properties of Refrigerant 134a.
  • Basic principles of energy transfer in mechanical systems.
NEXT STEPS
  • Study the thermodynamic properties of Refrigerant 134a in detail.
  • Learn about the continuity equation and its applications in fluid systems.
  • Explore energy transfer calculations in refrigeration cycles.
  • Investigate the kinetic energy formula and its relevance in thermodynamic systems.
USEFUL FOR

Mechanical engineers, refrigeration technicians, and students studying thermodynamics or fluid mechanics will benefit from this discussion.

onemoretomorrow
Messages
1
Reaction score
0
Hi guys i really need some help on this question.

Refrigerant 134a enters the compressor of a refrigeration system as saturated vapour at 0.14MPa and leaves as superheated vapour at 0.8MPa and 50 degrees celsius as a rate of 0.04kg/s. The suction area of the compressor is 10cm^2 and the discharge area 5cm^2. Determine the rates od energy transfer by mass into and out of the compressor, neglecting potential energy. Note the order of magnitude of the enthalpy and kinetic energy terms.

I can't seem to be able to get the value for the mass. can someone help? thanks
 
Physics news on Phys.org
Determine the rates od energy transfer by mass into and out of the compressor
One does not need mass, since the problem seems to be asking for energy on a per unit mass basis.

The kinetic energy per unit mass is simply V2/2. Thermodynamic properties are usually given on a per unit mass basis, e.g. specific enthalpy, h (J/kg), or internal energy, u (J/kg).

Mass flow rate is given - 0.04kg/s - and assuming the continuity equation, as steady-state, mass rate (in) = mass rate (out), otherwise there would be an accumulation (if mass flow in exceeds mass flow out) of the system.
 

Similar threads

Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K