How Is Engine Efficiency Calculated Using V1/V2 in Thermodynamic Cycles?

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The discussion focuses on calculating the efficiency of a thermodynamic engine operating through four processes: two adiabatic (A and C), one isochoric (D), and one isobaric (B). The user attempts to express the efficiency in terms of the volume ratio V1/V2 but concludes that it cannot be done solely with this ratio. They note that the work done is represented by the area enclosed in the process diagram, and the heat absorbed includes work done during process B and the internal energy gained. The conversation highlights the complexity of deriving efficiency in this context, particularly for an ideal diesel engine cycle. Ultimately, the user resolves their problem after further research on diesel cycle efficiency.
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Homework Statement


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Four thermodynamic processes A,B,C,D are shown in the picture. A and C are adiabatic processes. Pressure is held constant during B, and volume is constant during D. An engine run from A->B->C->D->... What is the efficiency of this engine (in terms of V1/V2)?

Homework Equations



p{ V }^{ \gamma }=const.\\ W=\int { PdV } \\ efficiency=\frac { W }{ { Q }_{ in }^{ } }

The Attempt at a Solution


This is a problem I encountered in an exam. I labeled all points with P1,P2,P3,V1,V2,V3. The work done is the area enclosed in the picture. Heat absorbed is (work done in B) + (internal energy gained in B). But I can't write the answer with only V1/V2. I am wondering whether there is an answer.
 
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The efficiency cannot be written in terms of only V1/V2. An ideal diesel engine has this type of cylce. So, you might do a search on efficiency of a diesel cycle.
 
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