How Is Momentum Conserved in a Two-Body Collision?

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Momentum conservation in a two-body collision requires considering both components of velocity. The initial momentum of the system is calculated using the mass and velocity of both objects, factoring in the angle of collision. The user initially only included the cosine component, leading to an incorrect calculation. To find the correct speed after the collision, both the cosine and sine components of the second object's velocity must be included. This adjustment will yield the accurate final speed of the combined masses.
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Hi.I have some confusion on this question ...here is the question

1.A(n) 2.6 kg object moving with a speed of
7.9 m/s collides with a(n) 3 kg object mov-
ing with a velocity of 7.4 m/s in a direction
56.1768◦ from the initial direction of motion
of the 2.6 kg object.What is the speed of the two objects after
the collision if they remain stuck together?
Answer in units of m/s

here is what i did but my answer out to be wrong .
Mass * velocity + Mass * velocity =( Mass +Mass)velocity

2.6 * 7.9 + 3*7.4 *cos56.1768 = (2.6 +3)v
20.54 +12.357 = 5.6v
so velocity = 5.8745 m/s

thank you.
 
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You're only considering the component of the velocity in the direction of the first object. That's why you did cos(56.1768). Don't forget to factor in the other component, namely, sin(56.1768). You should get the right answer if you do.
 
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