How Is the Average Power Output Calculated for an Airplane Propeller?

AI Thread Summary
The average power output of an airplane propeller is calculated using the formula Pav = Work done/time. In this case, the work done during the first 5 revolutions is 5.91 kJ, and the time taken is calculated to be approximately 1.65 seconds. The user initially misapplied the variables in their time calculation, confusing angular velocity with angular acceleration. Clarification is sought regarding the source of the known values, particularly the work done. Understanding how to correctly apply the equations and where the known values originate is crucial for accurate calculations.
mcchoy528

Homework Statement


An airplane propeller is 2.78 m in length (from tip to tip) and has a mass of 127 kg . When the airplane's engine is first started, it applies a constant torque of 1880 N⋅m to the propeller, which starts from rest.
Part D
What is the average power output of the engine during the first 5.00 rev ?

Known:α=23.0rad/s2
ω after making 5.00rev=38.0rad/s
Work done by engine during first 5 rev=5.91kJ

Homework Equations


Pav= Work done/time
θ=ω0t +1/2αt2

The Attempt at a Solution


Since ω0=0,
θ=1/2αt2
t= √(2*5*2π/38.0)=1.65s
Pav= 5.91/1.65=3.58kW

I don't know why my answer is incorrect. Can anyone help?
 
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Where do the "knowns" come from? Are you told this in the question? Where does the "work done during first 5 revs" come from? This is wrong. How is the work calculated?
In your equation for t, I think you've put ω instead of α in the denominator.
 
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