How is the Bethe-Bloch formula used in gamma-ray photon detection?

[FNL]

can some one give me a link or an article or his argument which Explain how the Bethe-Bloch formula is used to determine the energy of a gamma-ray photon stopped in a spark-chamber detector.

thanks

 

[malawi_glenn]

a gamma ray photon will undergo pair production, and it is the total amount of energy from those electrons and positrons that will be collected in an EM-calorimeter.

 

[FNL]

a gamma ray photon will undergo pair production, and it is the total amount of energy from those electrons and positrons that will be collected in an EM-calorimeter.

yes , it will be clear
thank you

 

[ZapperZ]

a gamma ray photon will undergo pair production, and it is the total amount of energy from those electrons and positrons that will be collected in an EM-calorimeter.

Is this really what is occurring in such a spark chamber? From what I've understood, all it requires is that the gamma ray causes ionization in the active gas in the spark chamber. Then by looking at the energy loss of these charge ions, one can apply the Bethe-Bloch to deduce the total energy of all the created charge particle and deduce the energy of the gamma photon that cause this ionization in the first place.

In such a low-density gas, one seldom creates pair production.

Zz.

 

[Astronuc]

Here's a brief article on a spark chamber.
http://eppog.web.cern.ch/eppog/Resources/SparkChamber.html
Another discussion - http://www.ep.ph.bham.ac.uk/index.php?page=general/outreach/SparkChamber/index

Firstly, pair production requires gamma ray energy of at least 1.0221 MeV. PP would be possible in the boundaries and plates/electrodes.

Secondly, I believe Compton scattering is more likely than pair prodcution, and then there is the photo-electric effect.

Is it inferred that the gamma-rays are much greater than 1.0221 MeV?

 

[malawi_glenn]

Yes ZapperZ, that is correct of you, forgot to read the last word 'spark chamber' properly :)

 

[FNL]

Thanks