How Is the Change in Linear Momentum Calculated in a Collision?

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In a collision involving a 0.118 kg mass moving at 8.49 m/s and rebounding at 1.07 m/s, the change in linear momentum is calculated by considering the direction of the velocities. The initial momentum is 1.00082 kg m/s, and the final momentum is -0.12646 kg m/s, leading to a total change of 1.128 kg m/s when accounting for the opposite direction of the rebound. The calculation involves taking the absolute value of the difference in momentum, as momentum is a vector quantity. Therefore, the change in linear momentum should be expressed as a positive value. Understanding the vector nature of momentum is crucial for accurate calculations in collision scenarios.
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A 0.118 kg mass is moving horizontally with a speed of 8.49 m/s when it strikes a vertical wall. The mass rebounds with a speed of 1.07 m/s. What is the magnitude of the change in linear momentum of the mass?

isn't the change just the difference in momentum? I did .118(8.49 - 1.07) to get .87556 kg m/s. this is wrong so i think the answer is .118(8.49+1.07) because it would be minus a negative velocity. so i got 1.128 kg m/s. but i don't know if this number should be negative or not.
 
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The change is, as you say, just the differnce in momentum.

But momentum is mv. And v (the velocity) is a vector and has a direction.
So deltaP = mv1 - mv2, but v1 and v2 are in opposite directions, so you have to (numerically) add them.

Since you are asked for a differnce, then take the absolute value, i.e. positive.
 
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