- #1
SwaggerJohn
- 4
- 0
A Huygens ocular is constructed of two thin lenses of focal lengths 10cm and 5cm respectively, separated by 7.5cm. The ocular is used in an astronomical telescope whose objective is 30cm to the left of the front lens of the ocular.
I need to find the position of the exit pupil, and then find the focal length of the ocular.
OK so I understand how to find the exit pupil and here is my idea:
Basically the exit pupil will be located where the image of the objective lens is created. So I found where the image of the objective lens will be created by Huygens ocular.
I used the following equation to do this: (x)(x') = f^2
where x is the distance of the object from the 2nd focal point of the thin lens, x' is the distance of the image formed measured from the 1st focal point of the thins lens, and f is the focal length of the thin lens.
So the image from the first lens is the object for the 2nd and eventually this gives that the exit pupil is 3cm to the right of the 2nd lens in the ocular.
Any ideas how to find the focal length of the ocular now?
I need to find the position of the exit pupil, and then find the focal length of the ocular.
OK so I understand how to find the exit pupil and here is my idea:
Basically the exit pupil will be located where the image of the objective lens is created. So I found where the image of the objective lens will be created by Huygens ocular.
I used the following equation to do this: (x)(x') = f^2
where x is the distance of the object from the 2nd focal point of the thin lens, x' is the distance of the image formed measured from the 1st focal point of the thins lens, and f is the focal length of the thin lens.
So the image from the first lens is the object for the 2nd and eventually this gives that the exit pupil is 3cm to the right of the 2nd lens in the ocular.
Any ideas how to find the focal length of the ocular now?
Last edited:
