How Is the Longest Wavelength of Light Determined for Anti-Reflective Coatings?

AI Thread Summary
The discussion focuses on determining the longest wavelength of light reflected from a glass surface coated with magnesium fluoride. The thickness of the coating is 95.6 nm, and the refractive indices of glass and the coating are 1.5 and 1.38, respectively. A calculation attempt incorrectly equates the thickness to a wavelength of 527 nm, prompting clarification on the relationship between film thickness and wavelength. Key factors include the conditions for strong reflection and the inversion of reflected waves at boundaries. Understanding these principles is essential for accurately calculating the wavelength of reflected light in anti-reflective coatings.
Barry Melby
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Homework Statement


A sheet of glass (nglass = 1.5) is coated with a 95.6-nm-thick layer of magnesium fluoride (ncoating = 1.38) to prevent reflection in the visible spectrum. Assume the incoming light is normal to the surface.
What is the longest wavelength of light strongly reflected from this coated surface?

Homework Equations

The Attempt at a Solution



95.6 = x/4(1.38) = 527 nm
This is incorrect however.
 
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Please show your reasoning.
Note: you have written 95.6 = 527 ... which is, indeed, false. I don't think that is what you meant.

Under what circumstances does a reflected wave invert?
What condition is needed for strong reflection off the top surface of the film?
 
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