How is the Lorentz Factor Derived?

Joeirvin
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Homework Statement


I am trying to show how the Lorentz factor is derived but i am unsure how to get past a certain stage..
2. Homework Equations / attempt
Let:
c = velocity of light.
v = the velocity as observed from where time t is measured.
D = distance AB.
t = time light occupies to pass from A to B.
t1 = time light occupies to return from B to A.
Firstly we can see that
t= D/(c+v)
And
t1= D/(c-v)
So for the total distance,
t+t1=D/(c+v)+D/(c+v)
Make a common denominator and add the two fractions,
t+t1=(D(c-V)+D(c+v))/((c+v)(c-v))
Expand the brackets,
(Dc+Dv+Dc-Dv)/(c^2+cv-cv-v^2)
Simplify, cancel out where possible,
(2Dc)/(c^2-v^2)
And take out the factor of 2D
t+t1=2D(c/(c^2-v^2)) or 2D(1/(c-(v^2/c))
( I am unsure whether or not taking it that far is right yet..)

Above is where i have arrived and the next step i am supposed to arrive at..
2D (c^2 / (c^2 - v^2)) = 2D (1 + (v^2 / c^2)]

Any help asap please?

thankyou
 
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Joeirvin said:
t = time light occupies to pass from A to B.
t1 = time light occupies to return from B to A.
What's A and B? Are they events? Points in space? Wouldn't this make t=t1?

Joeirvin said:
Firstly we can see that
t= D/(c+v)
And
t1= D/(c-v)
I'm not sure what you're doing, but this looks wrong.
 
It doesn't matter now, i decided to start over using a light clock idea, and it seemed to work perfectly. Thanks anyway
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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