How Is the Lower Bound of Neutrino Mass Calculated?

frazzle
Messages
11
Reaction score
0
I was wondering if anyone could help clarify this problem I am having.

Upon reading a section in a paper, I am a bit stuck as to how this value of the lower bound of the neutrino mass is reached here. I have highlighted the relevant part in the snapshot below:http://img487.imageshack.us/img487/3...inomass3fk.jpg Is there something missing from this passage, or am I just missing something blindingly obvious? I can't seem to understand how the two squared mass differences coupled with the assumption of hierarchy lead to the quoted value!

in case you're curious, the paper is:

http://arxiv.org/abs/astro-ph?papernum=0407207

thank you for reading!
 
Last edited by a moderator:
Physics news on Phys.org
no worries, I've figured it out now.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top