How Is Thermal Energy Produced in a Resistor During Capacitor Discharge?

AI Thread Summary
The discussion focuses on determining the rate of thermal energy production in a resistor during capacitor discharge. The correct formula for power dissipated in the resistor is P = i²R, where i is the current at a given time. The energy stored in the capacitor is not directly the rate of energy transfer to the resistor. The user is advised to find expressions for voltage and current as functions of time to accurately calculate power. Understanding these relationships is crucial for solving the problem effectively.
Daniiel
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I have a quick question.
part of one of my questions asks
"Find the rate at which thermal energy is produced in a resistor"
i havn't included the whole question because i don't think it matters, its just like the last part of it
so we have
http://edugen.wiley.com/edugen/courses/crs1650/art/math/halliday8019c27/math148.gif
thats the discharge of energy out of the capacitor
so
would the inverse of that be the rate at which the energy is moved into the resistor
like
1/u = 2ce/q (i left out a lot of things but thatsl ike the base of it)

orr
do you juts switch the e^- to e^+
because e^- is decay and e^+ is growth

yeh I am just abit confused which is right, or if either is right haha.
thanks
 
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Daniiel said:
I have a quick question.
part of one of my questions asks
"Find the rate at which thermal energy is produced in a resistor"
i havn't included the whole question because i don't think it matters,
It does matter. If the resistor is connected to the battery, thermal energy is constant with respect to time; if it is connected to a discharging capacitor (as seems to be the case here) then the thermal energy will be a function of time.
its just like the last part of it
so we have
http://edugen.wiley.com/edugen/courses/crs1650/art/math/halliday8019c27/math148.gif
thats the discharge of energy out of the capacitor
No. That's the energy stored in the capacitor at any time t.
so
would the inverse of that be the rate at which the energy is moved into the resistor
like
1/u = 2ce/q (i left out a lot of things but thatsl ike the base of it)

orr
do you juts switch the e^- to e^+
because e^- is decay and e^+ is growth

yeh I am just abit confused which is right, or if either is right haha.
thanks
None of the above. The rate at which energy is dissipated in the resistor (i.e. power dissipated) is given by
P = i2R, where i is the current in the resistor at a given time t. That's what you need to find an expression for.
 
what about
P(t)= V(t) I(t)
is that alright aswell?
 
Yes it is, but you will have to find two functions of time, V(t) and I(t). If you use P = I2R, you will need only I(t).
 
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