How is Velocity Distributed over 11 Dimensions?

SuicideSteve
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According to M-Theory there are 11 dimensions including time. 10 of these dimensions are spatial, so objects can move and therefore have velocity? Correct? According to Einstein's General Relativity whenever an object is not in motion in the three spatial dimensions, velocity is conserved through the passage of time. On the other hand light does not age because all of it's Velocity is in it's motion through three spatial dimensions.

Is the Velocity we see in the three visible dimensions "Shared" with other dimensions?

If part of an objects velocity is in another dimension wouldn't it be theoretically detectable?
 
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The velocity in the extra dimensions appears as mass in three dimensions. This follows from E^2= p^2 + m^2. The extra components of the p are seen as if they where part of the m.
 
Thank you for clearing that up for me.
 
arivero said:
The velocity in the extra dimensions appears as mass in three dimensions. This follows from E^2= p^2 + m^2. The extra components of the p are seen as if they where part of the m.
Hi all, it's my first post!

How do you get "E^2= p^2 + m^2" ? The units on left are joules, the units on right is kg(m/s) + kg...
When you say "The extra components of the "p" are seen as if they where part of the "m" do you mean that the components of velocity in the 7 other spatial dimensions are seen, in our everyday 3 spatial dimensions, as mass? If that is the case, shouldn't it be "E^2= (p^2)(m^2)" with the usual "v^2" (to make the units consistent: joules = joules) being replaced by "m^2"?

I guess I am having difficulty with unit consistency...
 
The equation should read:
( E / c )^2= p^2 + ( mc )^2

I'm aware that "natural units" are being used, but as under-grads, we were taught the importance of dimensional analysis and unit consistency. So natural units seem alarming at first sight.
 
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