How long can a 1.5 V battery light a flashlight bulb drawing 0.6A?

AI Thread Summary
A 1.5 V battery with 4.3 kJ of energy can power a flashlight bulb drawing 0.6 A. To determine how long it can light the bulb, the power consumed by the bulb must be calculated using the formula P = IV, which gives a power of 0.9 W. Since power is measured in Joules per second, the total energy in Joules (4,300 J) can be divided by the power (0.9 W) to find the time in seconds. Converting this time into hours provides the final answer. Understanding the relationship between voltage, current, and power is crucial for solving this problem.
Sarliz
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Homework Statement



You'll have to forgive me... I've got some rather poor Physics books with which to consult, so this may seem rather simple. I think I understand the concepts but I don't think I have all of the information from my sources to answer this problem.

A 1.5 V battery stores 4.3 kJ of energy. How long can it light a flashlight bulb that draws 0.6A?

Units should be in hours, but I'm not sure what to do with only having equations V = IR and I = E/R (where E is epsilon, of course). I don't know what part of this factors into time!
 
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The electric power in a DC circuit is P =IV. Is that enough to get you going?
 
Kurdt said:
The electric power in a DC circuit is P =IV. Is that enough to get you going?

Guess it'll have to be. Thanks.
 
Sarliz said:
Guess it'll have to be. Thanks.

If you have more questions I'll be happy to clarify :smile:

The units of power are of course Joules/second. That is where the time comes into it.
 

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