georg gill
- 151
- 6
one want to find the length of the two hypotenuses of the figure
Here is what I did. I looked at the small first with hypotenus unknown and adjacent=1 and the other cathetus unknown. Then i wanted to find max value of the smallest hypotenus.
tan\theta=\frac{1}{a}a=\frac{1}{tan\theta} Smallest hypotenus=sh
sh^2=1+\frac{1}{tan^2\theta}
i took derivative to find max value
sh=\sqrt{1+cot^2\theta}
\frac{d}{dx}sh=\frac{1}{\sqrt{1+cot^2\theta}} \cdot \frac{coth\theta}{sin^2\theta}
but this is equal to zero when \theta=\frac{\pi}{2} whoch gives sh=1which is obviously wrong since adjacent cathetus=1
What is wrong?
Last edited: