How Long Did the 23m Jump Last?

  • Thread starter Thread starter svtec
  • Start date Start date
AI Thread Summary
The discussion focuses on the physics of a man jumping from a bridge into a river 23.0 meters below. The jump lasts approximately 2.17 seconds, with the diver reaching a speed of 21.2 m/s upon impact with the water. A spectator on the bridge hears the splash 2.24 seconds after the diver's takeoff, considering the speed of sound in air at 340 m/s. Participants confirm the accuracy of these calculations while expressing the challenges of understanding physics concepts. The conversation highlights the importance of precise calculations in physics homework.
svtec
Messages
22
Reaction score
0
Question: A man is jumping into a river that is 23.0m below a bridge.

1. how long does the jump last?
answer: 2.17 seconds
2. how fast was the diver traveling upon impact with the water?
answer: 21.2 m/s
3. If the speed of sound in air is 340 m/s, how long after the diver took off did a spectator on the bridge hear the splash?
answer: 2.24 seconds

TIA...



-andrew
 
Physics news on Phys.org
Yes, those answers are correct. Is that what you wanted?
 
thanks... i was just checking because i suck at physics.[b(]

i don't have any answers in the back of the book and our homework is worth almost a quarter of our grade.

physics for scientists and engineers = hard.


-andrew
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top