How long does a cell live outside a living host?

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The lifespan of cells outside a living host varies significantly based on environmental conditions and the type of cell. Factors such as temperature, nutrient availability, and protective coverings influence cell viability. The definition of "live" is also crucial, as it relates to metabolic activity and overall health. Normal and cancerous cells may exhibit different lifespans depending on these variables. Understanding these factors is essential for accurately assessing cell longevity outside a host.
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Hi, how long does a cell, normal and cancerous, live outside a living host?

Thanks, Aoiro
 
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This probably depends on a lots... First of all.. define "live"... (Yeah -- right, we get into all kinds of interesting things there...)

Think about what environment you are putting it into... Would either cell "live" if you took it and threw it into an oven? Are you putting it in some nutrient solution at proper temperature? What type of cell is it? Does it have protective covering like some bacteria/spores? I'm no bio guru, but I think these things would matter more than the particular type... although what is the metabolism rate of each, and how in general does metabolism compare with viability/life?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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