How Long Does It Take for a Pencil to Fall?

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    Falling Pendulum
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The discussion revolves around calculating the time it takes for a pencil, balanced on its point, to fall, treating it as an inverted pendulum. The small angle approximation is suggested to simplify the math, despite concerns about its validity when the angle approaches π/2 during the fall. Initial attempts to solve the problem using the period of a pendulum and integration lead to confusion, particularly regarding the application of energy concepts with mass concentrated at the tip. Participants acknowledge the challenges of the problem and the necessity of assumptions in physics to facilitate calculations. The conversation concludes with a hint that the small angle approximation is a useful starting point, even if it may not hold perfectly in this scenario.
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Homework Statement


A pencil of length l = 0.2 m is balanced on its point. How much time does it take to fall? Assume that the pencil is a massless rod and all of its mass is at the tip. To make the math easier, assume the small angle approximation.


Homework Equations



theta (double dot) = g/l sin theta

T = 2 pi (l/g) ^ (1/2)


The Attempt at a Solution



Since the pencil seems to be an inverted pendulum and the fall would be only 1/4 of the period, I first tried T/4 = pi/2 (.2/9.8) ^ (1/2). But that is not a correct solution.

Next I tried to rearrange and integrate

1/sin theta d2theta = g/l dt2

1/sin theta = sin theta/ sin2theta= sin theta/(1 - cos2theta)

let u = cos theta so du=- sin theta d theta

Integral( 1/ u2 - 1) du = 1/2 ln(u - 1) - 1/2 ln (u + 1)

[ 1/2 ln (cos theta -1) - 1/2 ln (cos theta + 1)] d theta = gt/l dt

I get lost here because the cos pi/2 is zero which makes the above meaningless.

The way I interpret the problem, all the mass is at the balancing point. So how can you use energy to calculate potential difference or KE?

If someone could just give a hint as to the approach, I would be greatful.

Thank you.
 
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if the whole pencil can fall then θ will be π/2 how can the 'small angle approximation' hold?
 
Arkavo said:
if the whole pencil can fall then θ will be π/2 how can the 'small angle approximation' hold?

Sorry, I agree, but that was the problem that I was given.

I think as in a lot of physics problems the assumption is made to make a good approximation.

As in how to design an automatic chicken plucker: First you assume a perfectly symmetrical, spherical chicken...
 
The small angle approximation helps you to get started. ##\theta(0)=0## doesn't. :smile:
 
Answer to pencil problem

Attached is the answer for your falling pencil pleasure. Hope this helps someone.
 

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