How long to travel 150m at 26m/s with an acceleration of -2.5m/s^2?

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SUMMARY

The discussion focuses on calculating the time required to travel 150 meters at an initial speed of 26 m/s while decelerating at -2.5 m/s². The key calculations involve determining the stopping distance and the time taken to stop. Using the kinematic equations, it is established that the stopping distance is approximately 169 meters, indicating that the vehicle will not stop in time to avoid hitting the child. Therefore, the driver has no time to react effectively within the 150 meters available.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of acceleration and deceleration concepts
  • Familiarity with units of measurement in physics (meters, seconds)
  • Ability to perform algebraic calculations
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  • Study kinematic equations in detail, focusing on distance, speed, and time relationships
  • Learn about the effects of reaction time on stopping distances in driving scenarios
  • Explore real-world applications of physics in automotive safety and braking systems
  • Research methods to calculate stopping distances under various conditions (e.g., different speeds and accelerations)
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Drivers, automotive engineers, physics students, and anyone interested in understanding the dynamics of vehicle stopping distances and safety measures.

Erin Pashanov
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Driving along a steady speed of 26m/s and suddenly see a child 150m from you. Breaks can produce acceleration of -2.5m/s^2 but it takes time to get the foot from the gas to the brake pedal. How much time do you have, if to avoid hitting the child?
 
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What distance to come to a stop?
How much of the 150 m is left?
How long to travel that distance?
 
bhillyard said:
What distance to come to a stop?
How much of the 150 m is left?
How long to travel that distance?
I guess it is how long to travel the distance. I copied the exact question I got.
 

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