Let's see how to build a coil to cancel that field. Since I don't expect an implementation. I'll be rounding off values here.
Choose AWG #0 Copper wire with a diameter over insulation of 0.5inch.
Dia. 0.5in. = 24 Turns/Ft. = 126 720 Turns/mile
Res Ohm/1000Ft = 0.1 Ohms =
5.28 0.528 Ohms/Mile
Weight = 3.13ft/pound = 5280/3.13 = 1687lb/mi
Current rating 150A
5E8 Ampere-Turns needed
Earth Circumference = 24000 Miles
5E8AT/150A = 3.3E6 Turns * 24000 = 8E10 miles of wire
3.3E6/126720 Turns per mile = one-layer winding 26.3 Miles wide
3.3E6 Turns * 24000 = 8E10 miles of wire
8E10 * 16871lb/mi = 1.35E15 pounds of wire
8E10 miles *
5.28 0.528 Ohms per mile = 4.224E
11 10 Ohms
150A * 4.224E
11 10 = 6.3E
1312[/color] Volts to drive the coil
With 1.35E15 pounds of Copper wire needed and Global Copper production of 5E10 pounds per year, you would need 27000 years to mine the Copper.
It looks like Earth-sized Helmholtz coils won't be in our lifetime.
Cheers,
Tom