How many atoms of oxygen are present in 300 grams of calcium

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To find the number of oxygen atoms in 300 grams of calcium carbonate (CaCO3), first calculate the number of moles of CaCO3 using its molar mass of 100 g/mol. Divide 300 grams by 100 g/mol to get 3 moles of CaCO3. Since each molecule of CaCO3 contains three oxygen atoms, multiply the number of moles (3) by 3 to find the total number of moles of oxygen atoms, resulting in 9 moles of oxygen. Finally, convert moles of oxygen to atoms by multiplying by Avogadro's number (approximately 6.022 x 10^23), yielding about 5.43 x 10^24 oxygen atoms in 300 grams of calcium carbonate.
NeerajKarthi
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Homework Statement


How many atoms of oxygen are present in 300 grams of calcium carbonate?

molar mass of CaCO3 = 100g

Homework Equations


The Attempt at a Solution


I don't know how to proceed.
Can anyone please help me out by giving the forulae or steps on how to do this problem.
 
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NeerajKarthi said:

Homework Statement


How many atoms of oxygen are present in 300 grams of calcium carbonate?

molar mass of CaCO3 = 100g

Homework Equations


The Attempt at a Solution


I don't know how to proceed.
Can anyone please help me out by giving the forulae or steps on how to do this problem.
Have you studied the concept of the mole in chemistry?

http://www.bbc.co.uk/education/guides/zysk7ty/revision/1
 
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