How many kg Uranium is needed for 5kW produced?

AI Thread Summary
To determine how many kilograms of uranium are needed to produce 5 kW of power, the energy released per decay is 5.6 MeV, and the half-life of uranium is 87.7 years. The calculation involves using the equation E = Pt to find the total energy required over time. Additionally, the mass-energy equivalence can be applied using Q = (mass defect) * 931.5 MeV/c^2 to convert energy to mass. Understanding the number of decays per second necessary to achieve the desired power output is crucial for solving the problem.
Narud
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Member advised to show more effort in the attempt at solution.

Homework Statement



Energy released is 5.6MeV, 5kW is produced, Half life = 87.7 years for Uranium
Need to find how many kg you need to produced that much power.

Homework Equations



E = Pt, Q = (mass defect) * 931.5MeV/c^2

The Attempt at a Solution



I solved for the energy released to be 5.6MeV as stated above, except I'm not sure how to find the amount required for that power produced...
 
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Narud said:

Homework Statement



Energy released is 5.6MeV, 5kW is produced, Half life = 87.7 years for Uranium
Need to find how many kg you need to produced that much power.

Homework Equations



E = Pt, Q = (mass defect) * 931.5MeV/c^2

The Attempt at a Solution



I solved for the energy released to be 5.6MeV as stated above, except I'm not sure how to find the amount required for that power produced...
If I'm not wrong, are you the same person https://physics.stackexchange.com/q/382031/149663?

The two questions match amazingly.
 
Wrichik Basu said:
If I'm not wrong, are you the same person https://physics.stackexchange.com/q/382031/149663?

The two questions match amazingly.
Including the fact that the question seems to be about Plutinium 238 wich does have a half-life of 87.7 years.
Stackexchange wants you to show some effort on homework questions as well.

Since you know how much energy one decay produces, it should be easy to compute how many decays/second you need to get a certain power. You only need to convert some units.
 
willem2 said:
Stackexchange wants you to show some effort on homework questions as well.
True.
 
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