How many Newtons would it take to damage a car?

In summary, the conversation discusses the amount of force needed to damage a car in a head-on collision. It is mentioned that the length of the cars and their speeds can be used to calculate the force needed, but it is also noted that force alone is not enough to predict damage. Factors such as the area the force is spread over and the time derivative of the force also play a role. The conversation also suggests using different objects or materials to better understand the effects of force and pressure on damage.
  • #1
Alexander Baine
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I am working on a science project, just in my spare time, and for this project I needed to know the amount of force it would take one car to damage another car, but the same model (so same weight, strength etc.) thanks for you help

~ Alex
 
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  • #2
Say we are speaking of a head-on collision. If the lengths of the cars are compressed 2 m, the cars are damaged.

Say the speed of the cars is 100 km/h and the weight of the cars is known, you can calculate the mean decelleration and thus the force needed to bring them to a halt.
 
  • #3
Alexander Baine said:
I am working on a science project, just in my spare time, and for this project I needed to know the amount of force it would take one car to damage another car, but the same model (so same weight, strength etc.) thanks for you help
Professionals do this with crash tests. You cannot do it with physics. There are too many unknowns. It is an engineering problem. After a head-on crash that appears to result in no damage, energy absorbing bumpers may, in fact, have suffered irreversible changes. The next crash may not be as pretty.
 
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  • #4
Hesch said:
If the lengths of the cars are compressed 2 m, the cars are damaged.
"Damaged" is a bit of understatement here.
 
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  • #5
Say we are speaking of a head-on collision. If the lengths of the cars are compressed 2 m, the cars are damaged.

Say the speed of the cars is 100 km/h, the weight of the cars is known, you can calculate the mean decelleration and thus the force needed to bring them to a halt.

Sorry, I don't think I have posted the above, which is just a repetition of #2. Some technical error ?
 
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  • #6
Which part of the car is easiest to damage? The glass should be pretty easy, but I'm guessing that I can get a door panel to buckle by just pressing hard enough on it manually in the middle. If not, I'm sure I can do it by kicking. Better yet, I can "key" a car with almost no effort at all. So, if a one car scrapes the other car with virtually no force, damage will be done. Does this answer your question?
 
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  • #7
Force by itself is not going to be enough to predict damage. It depends on the area that the force is spread over, and it also depends on the time derivative of the force. (A constant force can't cause vibration, whereas a varying force can.)
 
  • #8
What not use a different object...something other than a car...
Perhaps you can find a table that shows deformation characteristics of some simplier objects...a quick search did not turn up anything exciting.

I know different construction materials are rated for various loads...say 2" x 4" studs or 4" x4" posts [typically wood]. And I'm sure lally columns are similarly rated...

You might consider, for example, firing a pair of 2" x4" x8ft' pieces of lumber at each other and seeings if you can estimate some small initial deformations...

https://en.wikipedia.org/wiki/Compressive_strength

How far must a basket ball be dropped to deform 1" ? I have no idea; but you could could try figuring it out assuming a vacuum so there is no air resistance slowing it down...
 
  • #9
I expect the pressure at a given point of the car is more important than the force. I know (I have seen it) that it is possible to drive an awl through the bodywork by force of hand alone. The same force applied to a large object (say the hand itself) does almost no damage.
 
  • #10
Svein said:
I expect the pressure at a given point of the car is more important than the force. I know (I have seen it) that it is possible to drive an awl through the bodywork by force of hand alone. The same force applied to a large object (say the hand itself) does almost no damage.
This is pretty much the same thing bcrowell said in post #7 and is also similar to what I said in post #6 when I talked about "keying" a car.
 
  • #11
Chestermiller said:
This is pretty much the same thing bcrowell said in post #7 and is also similar to what I said in post #6 when I talked about "keying" a car.
Sorry. Sloppy reading.
 

1. How many Newtons can a car withstand before being damaged?

The amount of Newtons required to damage a car varies depending on the type and size of the car. However, on average, it would take about 20,000 Newtons of force to cause significant damage to a car.

2. Can a car be damaged by a single Newton of force?

It is highly unlikely that a single Newton of force would cause any noticeable damage to a car. Cars are designed to withstand much greater forces, such as those experienced during collisions or rough driving conditions.

3. How many Newtons would it take to dent a car?

Again, this depends on the type and size of the car, as well as the location of the dent. On average, it would take about 5,000 Newtons of force to create a dent in a car's body.

4. Are there certain parts of a car that are more susceptible to damage from Newtons?

Yes, the most vulnerable areas of a car are typically the front and rear bumpers, as well as the doors and fenders. These areas are more likely to sustain damage from forces, such as impacts or collisions.

5. How do Newtons compare to other units of force when it comes to damaging a car?

Newtons are a unit of force commonly used in the scientific community, but they are not typically used to measure the force required to damage a car. Other units, such as pounds or kilograms, are more commonly used for this purpose.

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