How many possible combinations can be made from 6 codons using base pairs?

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SUMMARY

The discussion focuses on calculating the total number of combinations from 6 specific codons: Leu, Asp, Phe, Ile, Pro, and Cys. Each codon has a defined number of possible base pair combinations: Leu (4), Asp (2), Phe (2), Ile (3), Pro (4), and Cys (2). The total combinations can be determined by multiplying the combinations of each codon together, resulting in a formula: 4 x 2 x 2 x 3 x 4 x 2. This approach effectively visualizes the problem of determining the overall combinations of codons.

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Arctangent
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This is a math question. really.

So I have 6 codons.
Leu-Asp-Phe-Ile-Pro-Cys.
Now as we've all learned from high school biology, codons are made up of 3 base pairs each.
We've also learned that the genetic code is degenerative, that is, more than one combination of base pairs can mean one single codon.

Leu has 4 different posisble combinations
Asp has 2
Phe has 2
Ile has 3
Pro has 4
and Cys has 2

The question is now, as you've probably guessed, to determine the number of possible ways to get Leu-Asp-Phe-Ile-Pro-Cys.

I'd rather not draw it out. Is there a good equation I could use/way to go about this?
 
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If there are 4 ways to get to City Leu from where you are, and 2 ways from Leu to Asp City, how many ways are there to get to Asp? Think about multiplying the combinations.
 
Thanks, that helped me visualize the problem!
 

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