How many possible combinations can be made from 6 codons using base pairs?

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To determine the total number of combinations for the sequence Leu-Asp-Phe-Ile-Pro-Cys, one must multiply the number of combinations for each codon. Leu has 4 combinations, Asp has 2, Phe has 2, Ile has 3, Pro has 4, and Cys has 2. The calculation involves multiplying these values together: 4 x 2 x 2 x 3 x 4 x 2. This approach effectively visualizes the problem and simplifies the process of finding the total combinations. The final result provides the total number of ways to form the specified sequence of codons.
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This is a math question. really.

So I have 6 codons.
Leu-Asp-Phe-Ile-Pro-Cys.
Now as we've all learned from high school biology, codons are made up of 3 base pairs each.
We've also learned that the genetic code is degenerative, that is, more than one combination of base pairs can mean one single codon.

Leu has 4 different posisble combinations
Asp has 2
Phe has 2
Ile has 3
Pro has 4
and Cys has 2

The question is now, as you've probably guessed, to determine the number of possible ways to get Leu-Asp-Phe-Ile-Pro-Cys.

I'd rather not draw it out. Is there a good equation I could use/way to go about this?
 
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Thanks, that helped me visualize the problem!
 
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