How Many Possible Committees Can Be Chosen from a Group of 8 Men and 9 Women?

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Homework Statement



A committee of seven is to be chosen from 8 men and 9 women.
a) how many possible committees are there?
b) how many committees contain at least 6 woment?
c) if bob and alice cannot be on the same committee because they cannot work together well, how many committees are possible?

Homework Equations





The Attempt at a Solution



Not sure where to start really... other than writing down every possible committee
 
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Hints:

(a) This is a combination, (8+9) choose 7.

(b) (committee of 7 with 6 women) + (committee of 7 with 7 women)

(c) (all committees) - (those with both Bob and Alice).

--Elucidus
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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