How many subsets of size three or less are in a n-object set

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The discussion centers on calculating subsets of size three or less from a set of n applicants. For part (a), the number of ways to select at most three applicants is given by the formula Σ from i=0 to 3 of the binomial coefficient C(n, i). Part (b) defines the total subsets of size at most three in a set of size n, which can also be expressed using binomial coefficients. The distinction between parts (a), (b), and (c) lies in the context of selection versus counting subsets, but the underlying calculations remain similar. Ultimately, all parts relate to the combinatorial concept of selecting subsets from a larger set.
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Homework Statement


(a) How many ways can at most three people out of a selection of ##n## applicants be selected for a job?
(b) How many subsets of size at most three are there in a set of size ##n##?
(c) How many ways can a given subset of size three or fewer be chosen for the job?

Homework Equations

The Attempt at a Solution


(a) There are ##\sum_{i=0}^3 \binom n i## ways.
(b) Define the set of n objects as ##A##. Then define a subset ##\sigma_i=\{x\in P(A): |x|\leq 3\}##. Now define a set of integers ##J=\{i\in \mathbb{N}:\sigma_i\cap \sigma_j=∅,\sum_i |\sigma_i|=n\}##. Now define ##S_k=\cup_{j \in J} \sigma_j##, and so for a given selection of subsets, the number of subsets of at most size three is: ##\frac{n!}{\Pi_{\sigma_i\in S_k} |\sigma_i|!}##. And so the total number of possible subsets of at most size three is: ##\sum_{k=1}^{|\{\text{possible arrangements of subsets of at most three}\}|}\frac{n!}{\Pi_{\sigma_i\in S_k} |\sigma_i|!}##
 
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Your answer to (a) is correct.

Do you think (b) or (c) differs from (a) other than in how they are expressed? If so, how? (Note that in none of the three cases are the subsets specified to be ordered).
 
andrewkirk said:
Do you think (b) or (c) differs from (a) other than in how they are expressed? If so, how?

Well, in part (a), you're choosing one subset of at most size three to be selected for a job, while part (b) asks for how many of these possible subsets there are in the n-size set. If I had to hazard a guess, I'd say that they're both the same, in the respect that ##\binom n k## for ##k\leq 3## counts how many subsets of ##k## elements can be formed from a set of ##n## objects. So I'll take a shot in the dark and say that the answer to part (a) is the same as in part (b), or part (b)'s answer looks something like: ##\binom n k## for ##k\leq 3##.
 
Eclair_de_XII said:
Well, in part (a), you're choosing one subset of at most size three to be selected for a job, while part (b) asks for how many of these possible subsets there are in the n-size set. If I had to hazard a guess, I'd say that they're both the same, in the respect that ##\binom n k## for ##k\leq 3## counts how many subsets of ##k## elements can be formed from a set of ##n## objects. So I'll take a shot in the dark and say that the answer to part (a) is the same as in part (b), or part (b)'s answer looks something like: ##\binom n k## for ##k\leq 3##.
Yes, the set of applicants is a set of size ##n## and the set of people selected for the job is a subset of that, of size at most three.

The three questions are the same, just expressed differently.
 
Huh, thanks.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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