How many ways can you arrange 7 students with specific groupings in a line?

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SUMMARY

The arrangement of 7 students, consisting of 2 Americans, 2 Russians, and 3 Indians, requires that the Americans and Indians remain grouped together. By treating the 2 Americans as one unit and the 3 Indians as another unit, the problem simplifies to arranging 4 units: the American group, the Indian group, and the 2 Russians. The total arrangements are calculated as 4! for the units, multiplied by 2! for the Americans and 3! for the Indians, resulting in 288 ways to arrange the students while maintaining the specified groupings.

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I have a question here. Please can someone solve this. The question is:
There are 7 students of whom 2 are Americans, 2 are Russians and 3 Indians. hey have to stand in a line so that the two Americans are always together and the three Indians are always together. In how many ways can this be done??
 
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If there were only one American and one Indian, could you solve this problem?
 
In other words, treat the two Americans and the three Indians as being single persons. Once you know how many ways you can line up those "4 people", think about how many new ways you could get by interchanging the Americans only or interchanging the Indians only.
 

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